(D^2+2D+1)=1

Solution for (D^2+2D+1)=1 equation:

Simplifying
(D2 + 2D + 1) = 1

Reorder the terms:
(1 + 2D + D2) = 1

Remove parenthesis around (1 + 2D + D2)
1 + 2D + D2 = 1

Add '-1' to each side of the equation.
1 + 2D + -1 + D2 = 1 + -1

Reorder the terms:
1 + -1 + 2D + D2 = 1 + -1

Combine like terms: 1 + -1 = 0
0 + 2D + D2 = 1 + -1
2D + D2 = 1 + -1

Combine like terms: 1 + -1 = 0
2D + D2 = 0

Solving
2D + D2 = 0

Solving for variable 'D'.

Factor out the Greatest Common Factor (GCF), 'D'.
D(2 + D) = 0

Subproblem 1
Set the factor 'D' equal to zero and attempt to solve:

Simplifying
D = 0

Solving
D = 0

Move all terms containing D to the left, all other terms to the right.

Simplifying
D = 0
Subproblem 2
Set the factor '(2 + D)' equal to zero and attempt to solve:

Simplifying
2 + D = 0

Solving
2 + D = 0

Move all terms containing D to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + D = 0 + -2

Combine like terms: 2 + -2 = 0
0 + D = 0 + -2
D = 0 + -2

Combine like terms: 0 + -2 = -2
D = -2

Simplifying
D = -2
Solution
D = {0, -2}